Integrand size = 29, antiderivative size = 201 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {1}{256} \left (10 a^2+3 b^2\right ) x-\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {2 a b \cos ^9(c+d x)}{9 d}+\frac {\left (10 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{256 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac {\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d} \]
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Time = 0.19 (sec) , antiderivative size = 201, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.276, Rules used = {2990, 2645, 14, 3279, 466, 393, 205, 209} \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=-\frac {\left (10 a^2+11 b^2\right ) \sin (c+d x) \cos ^7(c+d x)}{80 d}+\frac {\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{480 d}+\frac {\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{384 d}+\frac {\left (10 a^2+3 b^2\right ) \sin (c+d x) \cos (c+d x)}{256 d}+\frac {1}{256} x \left (10 a^2+3 b^2\right )+\frac {2 a b \cos ^9(c+d x)}{9 d}-\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {b^2 \sin (c+d x) \cos ^9(c+d x)}{10 d} \]
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Rule 14
Rule 205
Rule 209
Rule 393
Rule 466
Rule 2645
Rule 2990
Rule 3279
Rubi steps \begin{align*} \text {integral}& = (2 a b) \int \cos ^6(c+d x) \sin ^3(c+d x) \, dx+\int \cos ^6(c+d x) \sin ^2(c+d x) \left (a^2+b^2 \sin ^2(c+d x)\right ) \, dx \\ & = \frac {\text {Subst}\left (\int \frac {x^2 \left (a^2+\left (a^2+b^2\right ) x^2\right )}{\left (1+x^2\right )^6} \, dx,x,\tan (c+d x)\right )}{d}-\frac {(2 a b) \text {Subst}\left (\int x^6 \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d} \\ & = \frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}-\frac {\text {Subst}\left (\int \frac {b^2-10 \left (a^2+b^2\right ) x^2}{\left (1+x^2\right )^5} \, dx,x,\tan (c+d x)\right )}{10 d}-\frac {(2 a b) \text {Subst}\left (\int \left (x^6-x^8\right ) \, dx,x,\cos (c+d x)\right )}{d} \\ & = -\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {2 a b \cos ^9(c+d x)}{9 d}-\frac {\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac {\left (10 a^2+3 b^2\right ) \text {Subst}\left (\int \frac {1}{\left (1+x^2\right )^4} \, dx,x,\tan (c+d x)\right )}{80 d} \\ & = -\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {2 a b \cos ^9(c+d x)}{9 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac {\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac {\left (10 a^2+3 b^2\right ) \text {Subst}\left (\int \frac {1}{\left (1+x^2\right )^3} \, dx,x,\tan (c+d x)\right )}{96 d} \\ & = -\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {2 a b \cos ^9(c+d x)}{9 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac {\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac {\left (10 a^2+3 b^2\right ) \text {Subst}\left (\int \frac {1}{\left (1+x^2\right )^2} \, dx,x,\tan (c+d x)\right )}{128 d} \\ & = -\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {2 a b \cos ^9(c+d x)}{9 d}+\frac {\left (10 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{256 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac {\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d}+\frac {\left (10 a^2+3 b^2\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\tan (c+d x)\right )}{256 d} \\ & = \frac {1}{256} \left (10 a^2+3 b^2\right ) x-\frac {2 a b \cos ^7(c+d x)}{7 d}+\frac {2 a b \cos ^9(c+d x)}{9 d}+\frac {\left (10 a^2+3 b^2\right ) \cos (c+d x) \sin (c+d x)}{256 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{384 d}+\frac {\left (10 a^2+3 b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{480 d}-\frac {\left (10 a^2+11 b^2\right ) \cos ^7(c+d x) \sin (c+d x)}{80 d}+\frac {b^2 \cos ^9(c+d x) \sin (c+d x)}{10 d} \\ \end{align*}
Time = 0.46 (sec) , antiderivative size = 193, normalized size of antiderivative = 0.96 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {6300 b^2 c+12600 a^2 d x+3780 b^2 d x-15120 a b \cos (c+d x)-6720 a b \cos (3 (c+d x))+1080 a b \cos (7 (c+d x))+280 a b \cos (9 (c+d x))+5040 a^2 \sin (2 (c+d x))+630 b^2 \sin (2 (c+d x))-2520 a^2 \sin (4 (c+d x))-1260 b^2 \sin (4 (c+d x))-1680 a^2 \sin (6 (c+d x))-315 b^2 \sin (6 (c+d x))-315 a^2 \sin (8 (c+d x))+\frac {315}{2} b^2 \sin (8 (c+d x))+63 b^2 \sin (10 (c+d x))}{322560 d} \]
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Time = 1.26 (sec) , antiderivative size = 172, normalized size of antiderivative = 0.86
method | result | size |
parallelrisch | \(\frac {1260 \left (8 a^{2}+b^{2}\right ) \sin \left (2 d x +2 c \right )+2520 \left (-2 a^{2}-b^{2}\right ) \sin \left (4 d x +4 c \right )+210 \left (-16 a^{2}-3 b^{2}\right ) \sin \left (6 d x +6 c \right )+315 \left (-2 a^{2}+b^{2}\right ) \sin \left (8 d x +8 c \right )+25200 a^{2} d x +7560 b^{2} d x -30240 a b \cos \left (d x +c \right )-13440 a b \cos \left (3 d x +3 c \right )+2160 a b \cos \left (7 d x +7 c \right )+560 a b \cos \left (9 d x +9 c \right )+126 b^{2} \sin \left (10 d x +10 c \right )-40960 a b}{645120 d}\) | \(172\) |
derivativedivides | \(\frac {a^{2} \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{8}+\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{48}+\frac {5 d x}{128}+\frac {5 c}{128}\right )+2 a b \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \left (\sin ^{2}\left (d x +c \right )\right )}{9}-\frac {2 \left (\cos ^{7}\left (d x +c \right )\right )}{63}\right )+b^{2} \left (-\frac {\left (\sin ^{3}\left (d x +c \right )\right ) \left (\cos ^{7}\left (d x +c \right )\right )}{10}-\frac {3 \left (\cos ^{7}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{80}+\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{160}+\frac {3 d x}{256}+\frac {3 c}{256}\right )}{d}\) | \(183\) |
default | \(\frac {a^{2} \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{8}+\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{48}+\frac {5 d x}{128}+\frac {5 c}{128}\right )+2 a b \left (-\frac {\left (\cos ^{7}\left (d x +c \right )\right ) \left (\sin ^{2}\left (d x +c \right )\right )}{9}-\frac {2 \left (\cos ^{7}\left (d x +c \right )\right )}{63}\right )+b^{2} \left (-\frac {\left (\sin ^{3}\left (d x +c \right )\right ) \left (\cos ^{7}\left (d x +c \right )\right )}{10}-\frac {3 \left (\cos ^{7}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{80}+\frac {\left (\cos ^{5}\left (d x +c \right )+\frac {5 \left (\cos ^{3}\left (d x +c \right )\right )}{4}+\frac {15 \cos \left (d x +c \right )}{8}\right ) \sin \left (d x +c \right )}{160}+\frac {3 d x}{256}+\frac {3 c}{256}\right )}{d}\) | \(183\) |
risch | \(\frac {5 a^{2} x}{128}+\frac {3 b^{2} x}{256}-\frac {3 a b \cos \left (d x +c \right )}{64 d}+\frac {b^{2} \sin \left (10 d x +10 c \right )}{5120 d}+\frac {a b \cos \left (9 d x +9 c \right )}{1152 d}-\frac {\sin \left (8 d x +8 c \right ) a^{2}}{1024 d}+\frac {\sin \left (8 d x +8 c \right ) b^{2}}{2048 d}+\frac {3 a b \cos \left (7 d x +7 c \right )}{896 d}-\frac {a^{2} \sin \left (6 d x +6 c \right )}{192 d}-\frac {\sin \left (6 d x +6 c \right ) b^{2}}{1024 d}-\frac {\sin \left (4 d x +4 c \right ) a^{2}}{128 d}-\frac {\sin \left (4 d x +4 c \right ) b^{2}}{256 d}-\frac {a b \cos \left (3 d x +3 c \right )}{48 d}+\frac {a^{2} \sin \left (2 d x +2 c \right )}{64 d}+\frac {\sin \left (2 d x +2 c \right ) b^{2}}{512 d}\) | \(228\) |
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Time = 0.37 (sec) , antiderivative size = 149, normalized size of antiderivative = 0.74 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {17920 \, a b \cos \left (d x + c\right )^{9} - 23040 \, a b \cos \left (d x + c\right )^{7} + 315 \, {\left (10 \, a^{2} + 3 \, b^{2}\right )} d x + 21 \, {\left (384 \, b^{2} \cos \left (d x + c\right )^{9} - 48 \, {\left (10 \, a^{2} + 11 \, b^{2}\right )} \cos \left (d x + c\right )^{7} + 8 \, {\left (10 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{5} + 10 \, {\left (10 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )^{3} + 15 \, {\left (10 \, a^{2} + 3 \, b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{80640 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 529 vs. \(2 (184) = 368\).
Time = 1.38 (sec) , antiderivative size = 529, normalized size of antiderivative = 2.63 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\begin {cases} \frac {5 a^{2} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac {5 a^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac {15 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac {5 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac {5 a^{2} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac {5 a^{2} \sin ^{7}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{128 d} + \frac {55 a^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{384 d} + \frac {73 a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{384 d} - \frac {5 a^{2} \sin {\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} - \frac {2 a b \sin ^{2}{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{7 d} - \frac {4 a b \cos ^{9}{\left (c + d x \right )}}{63 d} + \frac {3 b^{2} x \sin ^{10}{\left (c + d x \right )}}{256} + \frac {15 b^{2} x \sin ^{8}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{256} + \frac {15 b^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{128} + \frac {15 b^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{128} + \frac {15 b^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{8}{\left (c + d x \right )}}{256} + \frac {3 b^{2} x \cos ^{10}{\left (c + d x \right )}}{256} + \frac {3 b^{2} \sin ^{9}{\left (c + d x \right )} \cos {\left (c + d x \right )}}{256 d} + \frac {7 b^{2} \sin ^{7}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{128 d} + \frac {b^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{10 d} - \frac {7 b^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} - \frac {3 b^{2} \sin {\left (c + d x \right )} \cos ^{9}{\left (c + d x \right )}}{256 d} & \text {for}\: d \neq 0 \\x \left (a + b \sin {\left (c \right )}\right )^{2} \sin ^{2}{\left (c \right )} \cos ^{6}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.63 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {210 \, {\left (64 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 120 \, d x + 120 \, c - 3 \, \sin \left (8 \, d x + 8 \, c\right ) - 24 \, \sin \left (4 \, d x + 4 \, c\right )\right )} a^{2} + 20480 \, {\left (7 \, \cos \left (d x + c\right )^{9} - 9 \, \cos \left (d x + c\right )^{7}\right )} a b + 63 \, {\left (32 \, \sin \left (2 \, d x + 2 \, c\right )^{5} + 120 \, d x + 120 \, c + 5 \, \sin \left (8 \, d x + 8 \, c\right ) - 40 \, \sin \left (4 \, d x + 4 \, c\right )\right )} b^{2}}{645120 \, d} \]
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Time = 0.45 (sec) , antiderivative size = 189, normalized size of antiderivative = 0.94 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {1}{256} \, {\left (10 \, a^{2} + 3 \, b^{2}\right )} x + \frac {a b \cos \left (9 \, d x + 9 \, c\right )}{1152 \, d} + \frac {3 \, a b \cos \left (7 \, d x + 7 \, c\right )}{896 \, d} - \frac {a b \cos \left (3 \, d x + 3 \, c\right )}{48 \, d} - \frac {3 \, a b \cos \left (d x + c\right )}{64 \, d} + \frac {b^{2} \sin \left (10 \, d x + 10 \, c\right )}{5120 \, d} - \frac {{\left (2 \, a^{2} - b^{2}\right )} \sin \left (8 \, d x + 8 \, c\right )}{2048 \, d} - \frac {{\left (16 \, a^{2} + 3 \, b^{2}\right )} \sin \left (6 \, d x + 6 \, c\right )}{3072 \, d} - \frac {{\left (2 \, a^{2} + b^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{256 \, d} + \frac {{\left (8 \, a^{2} + b^{2}\right )} \sin \left (2 \, d x + 2 \, c\right )}{512 \, d} \]
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Time = 11.74 (sec) , antiderivative size = 237, normalized size of antiderivative = 1.18 \[ \int \cos ^6(c+d x) \sin ^2(c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {5\,a^2\,x}{128}+\frac {3\,b^2\,x}{256}+\frac {5\,a^2\,{\cos \left (c+d\,x\right )}^3\,\sin \left (c+d\,x\right )}{192\,d}+\frac {a^2\,{\cos \left (c+d\,x\right )}^5\,\sin \left (c+d\,x\right )}{48\,d}-\frac {a^2\,{\cos \left (c+d\,x\right )}^7\,\sin \left (c+d\,x\right )}{8\,d}+\frac {b^2\,{\cos \left (c+d\,x\right )}^3\,\sin \left (c+d\,x\right )}{128\,d}+\frac {b^2\,{\cos \left (c+d\,x\right )}^5\,\sin \left (c+d\,x\right )}{160\,d}-\frac {11\,b^2\,{\cos \left (c+d\,x\right )}^7\,\sin \left (c+d\,x\right )}{80\,d}+\frac {b^2\,{\cos \left (c+d\,x\right )}^9\,\sin \left (c+d\,x\right )}{10\,d}-\frac {2\,a\,b\,{\cos \left (c+d\,x\right )}^7}{7\,d}+\frac {2\,a\,b\,{\cos \left (c+d\,x\right )}^9}{9\,d}+\frac {5\,a^2\,\cos \left (c+d\,x\right )\,\sin \left (c+d\,x\right )}{128\,d}+\frac {3\,b^2\,\cos \left (c+d\,x\right )\,\sin \left (c+d\,x\right )}{256\,d} \]
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